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trying to get property of non object in

trying to get property of non object in  using -'on,Control,page:







asked Oct 6, 2015 by mtabakade
edited Oct 6, 2015 by rajesh
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3 Answers

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Check the manual for mysql_fetch_object(). It returns an object, not an array of objects.

I'm guessing you want something like this

$results = mysql_query("SELECT * FROM sidemenu WHERE `menu_id`='".$menu."' ORDER BY `id` ASC LIMIT 1", $con);

$sidemenus = array();
while ($sidemenu = mysql_fetch_object($results)) {
    $sidemenus[] = $sidemenu;

Might I suggest you have a look at PDO. PDOStatement::fetchAll(PDO::FETCH_OBJ) does what you assumed mysql_fetch_object() to do

answered Oct 6, 2015 by pradip.bhoge
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Your error

Notice: Trying to get property of non-object in C:\wamp\www\phone\pages\init.php on line 22

Your comment

@22 is mname."

$sidemenu is not an object, and you are trying to access one of its properties.

That is the reason for your error.

answered Oct 6, 2015 by suyesh.lokhande
0 votes
mname as $sidemenu): ?>


$sidemenus = mysql_fetch_array($results);


answered Oct 6, 2015 by manju bhargava