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why do i need or null in mysql when counting rows with a condition

why do i need or null in mysql when counting rows with a condition  using -'mysql,theory'

There is a question about MySQL's COUNT() aggregate function that keeps popping into my head time to time. I would like to get some explanation to why it is working the way it is.

When I started working with MySQL I quickly learned that its COUNT(condition) seems only to work properly if condition also contains an OR NULL in the end. In case of more complicated COUNT conditions it was an empirical process to find out where to put it exactly. In MSSQL you do not need this OR NULL to get proper results, so I would like to know the explanation for it. So, here is an example.

Lets have a very basic table with the following structure and data:

  `value` int(11) NOT NULL

INSERT INTO test (value) VALUES(1);
INSERT INTO test (value) VALUES(4);
INSERT INTO test (value) VALUES(5);
INSERT INTO test (value) VALUES(6);
INSERT INTO test (value) VALUES(4);
INSERT INTO test (value) VALUES(4);
INSERT INTO test (value) VALUES(5);
INSERT INTO test (value) VALUES(2);
INSERT INTO test (value) VALUES(8);
INSERT INTO test (value) VALUES(1);

Scenario: I would like to count how many rows I have where the value = 4. An obvious solution would be to filter for it using a WHERE and do a COUNT(*) but I am interested in a COUNT(condition) based solution.

So, the solution that comes to my mind is:

  FROM test

The result is 10. This is obviously wrong.

Second attempt with OR NULL:

  FROM test

The result is 3. It is correct.

Can someone explain the logic behind this? Is this some bug in MySQL or is there a logical explanation why I need to add that strange-looking OR NULL to the end of the COUNT condition to get the correct result?

asked Oct 13, 2015 by nikhilapatil
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5 Answers

0 votes

COUNT() function accepts an argument, that is treated as NULL or NOT NULL. If it is NOT NULL - then it increments the value, and doesn't do anything otherwise.

In your case expression value=4 is either TRUE or FALSE, obviously both true and false are not null, that is why you get 10.

but I am interested in a COUNT(condition) based solution.

The count-based solution will be always slower (much slower), because it will cause table fullscan and iterative comparison of each value.

answered Oct 13, 2015 by kotmus2002
0 votes

This should reveal all

SELECT 4=4, 3=4, 1 or null, 0 or null


1   |   0   |   1   |   NULL


  1. COUNT adds up the columns / expressions that evaluate to NOT NULL. Anything will increment by 1, as long as it is not null. Exception is COUNT(DISTINCT) where it increments only if it is not already counted.

  2. When a BOOLEAN expression is used on its own, it returns either 1 or 0.

  3. When a boolean is OR-ed with NULL, it is NULL only when it is 0 (false)

To others

Yes if the count is the ONLY column desired, one could use WHERE value=4 but if it is a query that wants to count the 4's as well as retrieving other counts/aggregates, then the filter doesn't work. An alternative would have been SUM(value=4), e.g.

SELECT sum(value=4)
  FROM test
answered Oct 13, 2015 by gauravsinghal83
0 votes

COUNT(expression) counts the number of rows for which the expression is not NULL. The expression value=4 is only NULL if value is NULL, otherwise it is either TRUE (1) or FALSE (0), both of which are counted.

1 = 4         | FALSE
4 = 4         | TRUE
1 = 4 OR NULL | NULL
4 = 4 OR NULL | TRUE

You could use SUM instead:

SELECT SUM(value=4) FROM test

This is not particularly useful in your specific example but it can be useful if you want to count rows satisfying multiple different predicates using a single table scan such as in the following query:

    SUM(a>b) AS foo,
    SUM(b>c) AS bar,
    COUNT(*) AS total_rows
FROM test
answered Oct 13, 2015 by atulpariharmca
0 votes

I would suggest that you will find the more standard syntax moves better between different database engines and will always give the correct result.

 select count(*)
 from test
 where value = 4

Is the syntax you used a Mysql variant?

answered Oct 13, 2015 by gauravg.gwl
0 votes

It's because COUNT(expression) counts VALUES. In SQL theory, NULL is a STATE, not a VALUE and thus is it not counted. NULL is a state that means that field's value is unknown.

Now, when you write "value=4" this evaluates to boolean TRUE or FALSE. Since both TRUE and FALSE are VALUES, the result is 10.

When you add "OR NULL", you actually have "TRUE OR NULL" and "FALSE OR NULL". Now, "TRUE OR NULL" evaluates to TRUE, while "FALSE OR NULL" evaluates to NULL. Thus the result is 3, because you only have 3 values (and seven NULL states).

answered Oct 13, 2015 by ukohale