crop image in php

crop image in php  using -'php,gd,crop'

The code below crops the image well, which is what i want, but for larger images, it wotn work as well. Is there any way of 'zooming out of the image'

Idealy i would be able to have each image roughly the same size before cropping so that i would get good results each time

Code is


$image = $_GET['src']; // the image to crop
$dest_image = 'images/cropped_whatever.jpg'; // make sure the directory is writeable

$img = imagecreatetruecolor('200','150');
$org_img = imagecreatefromjpeg($image);
$ims = getimagesize($image);
imagecopy($img,$org_img, 0, 0, 20, 20, 200, 150);
echo '<img src="'.$dest_image.'" ><p>';


asked Sep 9, 2015 by rajesh
0 votes

4 Answers

0 votes

If you are trying to generate thumbnails, you must first resize the image using imagecopyresampled();. You must resize the image so that the size of the smaller side of the image is equal to the corresponding side of the thumb.

For example, if your source image is 1280x800px and your thumb is 200x150px, you must resize your image to 240x150px and then crop it to 200x150px. This is so that the aspect ratio of the image won't change.

Here's a general formula for creating thumbnails:

$image = imagecreatefromjpeg($_GET['src']);
$filename = 'images/cropped_whatever.jpg';

$thumb_width = 200;
$thumb_height = 150;

$width = imagesx($image);
$height = imagesy($image);

$original_aspect = $width / $height;
$thumb_aspect = $thumb_width / $thumb_height;

if ( $original_aspect >= $thumb_aspect )
   // If image is wider than thumbnail (in aspect ratio sense)
   $new_height = $thumb_height;
   $new_width = $width / ($height / $thumb_height);
   // If the thumbnail is wider than the image
   $new_width = $thumb_width;
   $new_height = $height / ($width / $thumb_width);

$thumb = imagecreatetruecolor( $thumb_width, $thumb_height );

// Resize and crop
                   0 - ($new_width - $thumb_width) / 2, // Center the image horizontally
                   0 - ($new_height - $thumb_height) / 2, // Center the image vertically
                   0, 0,
                   $new_width, $new_height,
                   $width, $height);
imagejpeg($thumb, $filename, 80);

Haven't tested this but it should work.


Now tested and working.

answered Sep 9, 2015 by rajesh
0 votes

imagecopyresampled() will take a rectangular area from $src_image of width $src_w and height $src_h at position ($src_x, $src_y) and place it in a rectangular area of $dst_image of width $dst_w and height $dst_h at position ($dst_x, $dst_y).

If the source and destination coordinates and width and heights differ, appropriate stretching or shrinking of the image fragment will be performed. The coordinates refer to the upper left corner.

This function can be used to copy regions within the same image. But if the regions overlap, the results will be unpredictable.

answered Sep 9, 2015 by rajesh
0 votes
$image = imagecreatefromjpeg($_GET['src']);

Needs to be replaced with this:

$image = imagecreatefromjpeg('images/thumbnails/myimage.jpg');

Because imagecreatefromjpeg() is expecting a string.
This worked for me.


answered Sep 9, 2015 by rajesh
0 votes
$image = imagecreatefromjpeg($_GET['src']);
$filename = 'images/cropped_whatever.jpg'

Must be replaced with:

$image = imagecreatefromjpeg($_GET['src']);

Then it will work!

answered Sep 9, 2015 by rajesh